Question

Geometry question concerning distance from point A to point B. Question is the first reply. Find the distance between points M(6,16) and Z(-1,14) to the nearest tenth

Answer 1

Find the distance between points M(6,16) and Z(-1,14) to the nearest tenth

Answer 2

think method first
from 6 to -1 is 7 units
from 16 to 14 is 2 units
pythagoras gives
\[\sqrt{7^2+2^2}\]

Answer 3

i found it easier with the thinking method after i understood it. does a thinking method apply here as well?

Answer 4

ah thats what youre doing

Answer 5

im sorry your comment just showed up

Answer 6

For this problem, you will need to use the Pythagorean theorem. On the x-axis, the points move 7 units, while on the y-axis, the points move 2 units. Knowing that one side of your triangle is 7 units long and the other side is 2 units long, you can square 7 and 2, then add them, being equal 49+4=53. Then, you need to find the square root of 53. The equation is a^2+b^2=c^2, c^2 being the side you want to find.

Answer 7

i know Pythagorean theorem. that will make this a lot easier.

Answer 8

yes
you have a right triangle
the base has length 7 (from 6 to -1)
the height has length 2 (from 16 to 14)
the hypotenuse is the distance you are looking for
via pythagoras it is
\[d^2=a^2+b^2\\
d^2=7^2+2^2\\
d=\sqrt{7^2+2^2}\]

Answer 9

let me try it

Answer 10

k

Answer 11

7.3 units

Answer 12

rounded to the tenths place

Answer 13

let me check it
looks right
did you get
\[\sqrt{53}\] first?

Answer 14

yeah 7.3 rounded

Answer 15

yes

Answer 16

then took the square root of 53

Answer 17

got 7.28

Answer 18

rounded

Answer 19

you are right