The velocity v, in meters per second, is given as a function of time t, in seconds, by v(t)=-0.539t^2+1.35t-7.29. What is the acceleration at time t = 3.21 s?

-i took the derivative and that didn't seem to work, i also did it twice to see if i did something wrong, but that didn't work either. please help :)

Question

The velocity v, in meters per second, is given as a function of time t, in seconds, by v(t)=-0.539t^2+1.35t-7.29. What is the acceleration at time t = 3.21 s?

-i took the derivative and that didn't seem to work, i also did it twice to see if i did something wrong, but that didn't work either. please help :)

abhisar · Answer

v(t)=$\sf -0.539t^2+1.35t-7.29\ Acceleration=\frac{dv}{dt}=-1.078t+1.35\ Plug~in~the~value~of~t$

anonymous · Answer

i figured it out last night, but thanks again :)

anonymous · Answer

i didn't put the negative sign, minor mistake