Question

2. The electrolyte in automobile lead storage batteries is a 3.75 M sulfuric acid solution that has a density of 1.230 g/mL. Calculate the mass percent, molality, and mol fraction of the sulfuric acid.
i am so lost dont know how to get the kg of solvent

Answer 1

\[1.230 g/ml*1000ml/L=1.230*10^3 g/L\]
\[3.75 mol*((2*1)+(32*1)+(16*4)) g H2SO4/1 mol=368 g H2SO4\]
\[1230.0 g Solution-368 g (H2SO4)=862 g H2O \]
\[Mass Percentage of H2SO4=(mass of H2SO4/mass of solution)*100\]
\[Mass Percentage of H2SO4=(368.0 g /1230.0g)*100%=29.9% \]

Answer 2

\[Molality=moles of solute/Kilograms of Solvent \]\[Molality=3.75 mol H2SO4/862*1kg H2O/1000g H2O \]