Question

4+9+14+19....+49. the sum of the sequence is?

Answer 1

apply artmtic progrssn formula...

Answer 2

Refer to the Mathematica 9 Home Edition attachment.

Answer 3

This is an arithmetic progression with a common difference of 5 and having the first term = 4.

a = 4
l = 49
d = 5
n = ?

Find n using this formula: l = a + (n-1)d
After finding 'n'.

Use the formula for the sum of an arithmetic progression: S = (n/2) * [2a + (n-1)d]

Answer 4

use \[l=a+(n-1)d\] to get n value
number of terms will be 10
and use \[\sum=(n/2)*(a+l)\]for sum of sequence.
answer will be 265

Answer 5

95