Describe the motion of a particle with position (x,y) as t varies in the given interval.
\[x=5sint~~~y=2cost~~~~~-\pi \le t \le 5\pi\]
@ganeshie8
from the first glance it looks like an ellipse, what do u think ?
I understand it's an ellipse but I don't understand why it moves clockwise around the ellipse 3 times, maybe just the drawing I don't understand haha.
period of sint is 2pi so one complete revolution = 2pi radians, yes ?
|dw:1409902062553:dw|
we don't know orientation yet, but we can see that [-pi, 5pi] has 3 full periods in it : (5pi - -pi)/(2pi) = 6pi/2pi = 3
so it makes 3 full revolutions starting at SOME point and moving in SOME direction we need to find these starting point and direction
Ah right right, thank you so much :P!
at t = -pi, (x,y) = (0, -2) : |dw:1409902254176:dw|
thats the starting position, you need to figure out whether the particle moves in clockwise or counterclockwise
we need to plot atleast TWO more points to know the orientation unambiguously
Yeah I got it, as t goes from - pi to 5 pi, (0,-2) is the start point and moves clockwise around 3 times. Thanks Ganeshie ^.^
:) yes and we need to plot the points within the same period.. otherwise there will be a clash
or else if we recall transformations in xy plane : (x, y) = (cos, sin) : counterclockwise rotation (x, y) = (sin, cos) : clockwise rotation
that tells immediately the orientation of particle
Yup, can I ask one more just to confirm?
yeah sure il try
\[x=3+2cost~~~y=1+2sint~~~~~~\pi/2 \le t \le 3\pi/2\] for this what I thought of was x = h+rcost y = k+sint which gives an equation of a circle so I got (x-3)^2+(y-1)^2=4
start point (3,3) moving counterclockwise
looks perfect ! but do you really get a full circle ?
No it should be half of a circle I think
you should draw it
y=k+rsint* yeah I'm drawing it now haha
one half of a circle
diagram
diagram tells everything - startpoint, endpoint and orientation
|dw:1409903747363:dw|
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