Question

Write y = 2(x - 4)2 + 7 in standard form. Using this standard form of the equation, type the values for a,b and c separated by commas without using spaces in the given box.

Answer 1

open (x-4)^2 first, what do you have?

Answer 2

x ^2 −8x+16 ?

Answer 3

yup, now combine all, y = 2(x-4)^2 +7 by replace what you have above in.

Answer 4

not yup for your last comment

Answer 5

i dont understand ?

Answer 6

a=1, b=−8, c=16

Answer 7

\[y = 2\color{red}{(x-4)^2}+7\\y = 2\color{red}{(x^2-8x+16)}+7\]
open the bracket, what do you get?

Answer 8

(x-4)^2?

Answer 9

a is not 1, you must open the bracket first.

Answer 10

i need values of a,b,c

Answer 11

yes,

Answer 12

its not saying anything different

Answer 13

a=2,b=-8c=16?

Answer 14

@Loser66 is ryt ,... follow him dude

Answer 15

I know, but!!! you have to follow step by step to get the standard form first, then consider the value of a, b, c
You skip the "open the bracket" step, so that, you are wrong.

Answer 16

i dont know how to do that

Answer 17

@desirae_michelle17 simply multiply the outer thing to inner things of bracket and add the contants..

Answer 18

im confused :/ which do i multiply >

Answer 19

multiply outer 2 with components in bracket

Answer 20

which bracket ?

Answer 21

16 & 112?

Answer 22

y=2(x2-8x+16)+7
y=2x2-16x+32+7
ryt

Answer 23

now add 32 and 7 that will be easy

Answer 24

39?

Answer 25

yup its c 39

Answer 26

b=16?

Answer 27

a= ?

Answer 28

\[2(x-4)^2+7\]=[2(x^2-8x+16)+7\]\[2x^2-16x+32+7\]\[2x^2-16x+39\]

Answer 29

a=2,b=16,c=39 ?

Answer 30

b = -16

Answer 31

okay thank you

Answer 32

my pleasure

Answer 33

my pleasure