The temperature of 6.24 L of a gas is increased from 25.0°C to 55.0°C at constant pressure. The new volume of the gas is
A. 13.7 L.
B. 5.67 L.
C. 6.87 L.
D. 2.84 L.
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OpenStudy (anonymous):
@thomaster please help?
OpenStudy (anonymous):
Let me try this was our lesson last month....
OpenStudy (anonymous):
@EngrChong i think its (C)
OpenStudy (anonymous):
Do you have a scientific calculator....?
OpenStudy (anonymous):
i do not
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OpenStudy (anonymous):
I have....I'll solve it....
OpenStudy (anonymous):
Charles' law
OpenStudy (anonymous):
V/T=K
OpenStudy (jfraser):
to use the gas laws, you have to use the temperature in Kelvin, not Celsius or Farenheit
OpenStudy (anonymous):
You teach her @JFraser .....Im not so good at explaining....
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OpenStudy (anonymous):
K= C* + 273
OpenStudy (anonymous):
how would this situation play out? a demonstration? a drawing?
OpenStudy (anonymous):
K= 25.0 C* +273
K= 55.0 C* +273
OpenStudy (anonymous):
Can you do it from here?
OpenStudy (anonymous):
V1/T1=V2/T2
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OpenStudy (anonymous):
would you divide them ? its been a year since i took this class
OpenStudy (jfraser):
You have 3 of the 4 pieces you need: V1, T1, and T2. Rearrange the equation and solve for T2, then plug in the pieces and solve
OpenStudy (abmon98):
At Constant Pressure- When we increase the temperature, the molecules move more rapidly, gas expands as it occupies more volume. Use Charles Law to find V2.
V1/T1=V2/T2
Note: Temperature is measured in kelvin so add the values of temperature to 273