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OpenStudy (anonymous):
How many moles of H2 would be contained in 4.0 L of the gas at 202.6 kPa and 127°C?
A. 89.6 mol
B. 6.38 mol
C. 0.24 mol
D. 0.77 mol
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OpenStudy (anonymous):
@JFraser i think its (B)
OpenStudy (jfraser):
use the ideal gas law\[P*V = n*R*T\]just be sure to convert your temp to kelvin, just like before
OpenStudy (jfraser):
that's not what i get, check your values and make sure you're using the proper value for R based on the units of pressure
OpenStudy (anonymous):
i got (D)
OpenStudy (jfraser):
if you got D, then you forgot to convert the temperature to kelvin
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OpenStudy (anonymous):
oh. then let me redo it
OpenStudy (anonymous):
A
OpenStudy (jfraser):
it's not A, either. let me show you the setup
OpenStudy (jfraser):
starting with\[P*V = n*R*T\]is rearranged to solve for \(n\)\[n = \frac{P*V}{R*T}\]
OpenStudy (anonymous):
c?
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OpenStudy (anonymous):
or was i right with b?
OpenStudy (jfraser):
\[n = \frac{(202.6kPa)*(2.0L)}{(8.31\frac{kPa*L}{mol*K})*(400K)}\]
OpenStudy (jfraser):
the answer is C)
OpenStudy (jfraser):
when you work with gases, the temp has to be in K
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