Question

A lead fishing weight with a mass of 57g absorbs 146cal of heat. If its initial temperature is 47 degrees Celsius, what is its final temperature?

Answer 1

just apply Q=msdT
where dT means change in temp and s means specific heat capacity of object

Answer 2

I just don't know how to set it up

Answer 3

146=57*search the sp. heat capacity of object and put here(s)*( initial temp-final tep)
that is (146/957*s))+initial temp= final temp

now just do this and u will get ans

Answer 4

how did you get 957? I thought it was 57?

Answer 5

@ananata

Answer 6

@Zale101

Answer 7

Member the formula Q=mct
energy = mass * specific heat * temperature change

Answer 8

In here, you are solving for the temperature change since it's not given. Then after that, you'll add in the initial temp.

Answer 9

so is it (146*57*47)

Answer 10

146 cal of heat is the energy, convert that to joules

Answer 11

Q is always in joules

Answer 12

http://physics.csustan.edu/Ian/HowThingsWork/Topics/Refrigerator/SpecificHeat.htm

Answer 13

is it 610.28

Answer 14

Here are the units you must use for Q=mc(delta)T
Joules = grams * (Joules/g*K) * K
joules is Q
grams is the mass
(Joules/g*K) is C
Kelvins in change temp

why 610.28?

Answer 15

oh, yes, it's right for the Q

Answer 16

sorry about that

Answer 17

so let's plug that in Q=mc(delta)t

610.28 J =(57 g)(c)(t)

to find c, what is the specific heat capacity for lead?

Answer 18

so how would I write out my answer?

Answer 19

lead is 0.128

Answer 20

yep
so
610.28 J =(57 g)( 0.128)(t)
now solve for t

Answer 21

7.296

Answer 22

now what do you do?

Answer 23

the value will come of t = 83.64
so know 83.64-47 is ur ans