Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

help want a medal

OpenStudy (anonymous):

OpenStudy (anonymous):

@itsbribro

OpenStudy (anonymous):

@jcrider

OpenStudy (anonymous):

@Deepolisnoob

OpenStudy (deepolisnoob):

with what application do i open your document?

OpenStudy (deepolisnoob):

To do this problem, you subtract the denominator exponent from the numerator exponent. Your denominator exponent is 5, so x-5=-2 (Im only using exponents in the equation). if you plug in 3, your exponents will be left at -2. However, this is incorrect. \[(7^3)/(7^5)=1^{-2}\] To fix this, you add another exponent to your numerator. You will have \[7^4/7^5=1^1\] If you simplify one exponent from the numerator(square 7 once) you will have \[49^3/7^5=7^{-2}\]

OpenStudy (deepolisnoob):

So you must plug in 4 into the numerator in order for this equation to work

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!