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To do this problem, you subtract the denominator exponent from the numerator exponent. Your denominator exponent is 5, so x-5=-2 (Im only using exponents in the equation). if you plug in 3, your exponents will be left at -2. However, this is incorrect. \[(7^3)/(7^5)=1^{-2}\] To fix this, you add another exponent to your numerator. You will have \[7^4/7^5=1^1\] If you simplify one exponent from the numerator(square 7 once) you will have \[49^3/7^5=7^{-2}\]
So you must plug in 4 into the numerator in order for this equation to work
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