Question

Given the equation \[-4 \sqrt{x-3} = 12\] , solve for x and identify if it is an extraneous solution.

Answer 1

@phi

Answer 2

@campbell_st

Answer 3

is there an answer choice as no solution

Answer 4

x = 0, solution is not extraneous

x = 0, solution is extraneous

x = 12, solution is not extraneous

x = 12, solution is extraneous

Answer 5

Square both sides. What do you get?

Answer 6

Those are the possible answers

Answer 7

-4 (x-3) = 144???

Answer 8

Yes. Distribute the -4. What do you get?

Answer 9

-4x + 12 = 144

Answer 10

Oh I understand it now thank you!!!!

Answer 11

You are welcome.

Answer 12

This is wrong

Answer 13

You need to divide by -4 before you square both sides

Answer 14

Oh, it should be 16 not 4 when you squared.

Answer 15

Square both sides:
16(x - 3) = 144
divide both sides by 16:
x - 3 = 9
x = 12

Answer 16

Or do that, but dividing it by -4 would be much simpler

Answer 17

Put 12 back in the original equation:
-4 * 3 = -12 which is not equal to 12.

So x = 12 is an extraneous solution.

Answer 18

Aum, show your work for that last one, please? I can't see how you got there