limit of x---> infinity (1/e^x)????please help
0
please explain
As x goes to infinity e^x goes to infinity right?
yes
So what is 1/infinity? or, 1/(A REALLY LARGE NUMBER) It approaches 0.
i saw that min x--->-infinity (e^x)=0 is it something similar
even though for this its -infinity?
1/10 = .1 1/100 = .01 1/1000 = .001 1/10000 = .0001 1/100000 = .00001 Let the denominator go to 10^10^10^10 or something haha Well if you have: \[\lim_{x \rightarrow \infty} \frac{1}{e^x} = \lim_{x \rightarrow \infty} e^{-x}\] Just let x -> -x \[\lim_{x \rightarrow \infty} e^{-x} =\lim_{-x \rightarrow \infty} e^{x}=\lim_{x \rightarrow -\infty}e^{x} = 0\]
ohh wow i see okay so it works for both pos or neg infinity as im understanding
Well, since one is 1/e^x and the other is e^x.
If you had: \[\lim_{x \rightarrow \infty} e^x \rightarrow \infty\]
but it was neg infinity it would be 0?
*if
Thank you!
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