Question

Find a and b if (a+bi)^2=12+16i. I don't know what to do

Answer 1

well first try to expand that left hand side expression!

Answer 2

I got a^2+2abi-b^2=12+16i

Answer 3

Good
now put some term together \(a^2-b^2+2abi=12+16i\)
then \((a^2-b^2)+2abi=12+16i\)
Now apply the rule of equality of two complex numbers \(a+bi=c+di\)
then
\(a=c ~~~and~~~ b=d\)

Answer 4

So a^2-b^2 = 12, 2ab=16

Answer 5

good
those are you two equations
solve for a and b

Answer 6

THANK YOU :D

Answer 7

welcome