Question

can someone show me how to do this problem.
square root of 6a - 4 square root of 54a - 4 square root of 216a

Answer 1

So:\[\sqrt{6a-4}, \sqrt{54a-4}, \sqrt{216a}\] Right?

Answer 2

Is that the question? Are you trying to simplify it?

Answer 3

yes

Answer 4

1)
\[\sqrt{6a-4}\]
Split into this:
\[\sqrt{6a}*\sqrt{-1}*\sqrt{4}\]
Simplify that to:
\[\sqrt{6a}*2*i\]
This equals to:
\[2i\sqrt{6a}\]

Answer 5

You would do the same thing with the other 2, with \[\sqrt{216a}\] being the easier, as ther is no \[i\]

Answer 6

Wait, I think that might not be right ;)
You have this equation:\[\sqrt{6a-4}\]
Split that into
\[\sqrt{6a}+\sqrt{-4}\]
Change that to
\[\sqrt{6a}+\sqrt{4}\sqrt{-1}\]
This can be turned into
\[\sqrt{6a}+2i\]

Answer 7

I am new to this, so someone more qualified, please help

Answer 8

Is the question:

\[\sqrt{6a-4}\sqrt{54a-4}\sqrt{216a}\]

And you have to simplify that?

Answer 9

Hmm, that's possible. You would have to simplify everything first as much as possbile before doing it to make it easier

Answer 10

I know that:\[\sqrt{6a-4}\] is equal to:
\[\sqrt{2}\sqrt{3a-2}\]

Answer 11

That is a correct operation (above).

You cannot do this:
\[\sqrt{6a-4}\neq \sqrt{6a}-\sqrt{4}\]
So your answers with imaginary components are invalid.

Answer 12

Which is why the second interpretation of the question is more likely.

Answer 13

I was thinking that. Sorry ;)

Answer 14

That would be one long and complicated question, I think he is just missing some important piece of info on the question.

Answer 15

Haha, that's all right. If you are not sure of an operation then simply type it into wolfram alpha like this:

http://www.wolframalpha.com/input/?i=does+sqrt%286a-4%29%3Dsqrt%286a%29-sqrt%284%29

Answer 16

And yeah, that is a good point, I suppose we should just see if s/he comes back

Answer 17

WolframAlpha & MathMatica is an AWESOME combination. Great thing that you can use WolframAlpha inside MathMatica