sin(90-theta)=0.574 how do I solve this? Will give medal to best help.
most likely with an identity. what is sine, written as cosine, look like? they are complements after all
|dw:1410024473104:dw|
90-a = -(a-90) which matches your problem better
so, I dont know theta and am trying to solve for it, how do I do that?
well -sin(90-theta) = -0.574 sin(theta-90) = -0.574 cos(theta) = -0.574 theta = cos^-1 (-0.574 )
this is one approach
ive most likely read the problem a little off in my head
sin(90-theta)=0.574 we already have a 90-theta, i was reading it backwards .. so, sin(90-theta) = cos(theta)
I have to find theta so that resultant force of Fa and Fb is directed horizontally to the right. I have to find magnitude of Fr
\[\sin \left( 90-\theta \right)=\cos \theta=0.574, \theta =\cos^{-1} \left( 0.574 \right)=?\]
I've solved everything out to this point
|dw:1410024818246:dw| sin(90-a) = y/r cos(a) = y/r
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