Question

You roll two dice. What is the probability that the sum of the dice is greater than 6 and one die shows a 2? A 6 X 6 table of dice outcomes will help you to answer this question. a. 3/4 b. 1/9 c.1/18 d.4/21

Answer 1

O(S)= 36
and the one dice show 2 so other dice will be 5 and 6 i.e.(5,2),(6,2)
so O(A)=2
probability = O(A)/O(S)
=2 /36
=1/18 is the correct answer

Answer 2

it was not

Answer 3

what
?

Answer 4

why ?

Answer 5

for starters, it was a direct answer ....

Answer 6

okay how can i tell him ?

Answer 7

ask him to make a table

Answer 8

thats what i did and i got 1/9

Answer 9

lets review the table then

1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4
5
6

1+2+3+4+5+6 results is what im getting

Answer 10

and one shows a 2 .... lets factor that into the setup

Answer 11

1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8 <-- 2
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
^
2

Answer 12

lets look at here
there is one dice in which only 2 will come
and the other dice the number greater than 4 will come because according to yur question when the sum of two dice (5,2) =7 is greater than 6
(6,2)=8 is greater than 8
so only the two events are there
so we write it as O(A)=2
and the sample space is 36 ,there are 6 posiblities in every dice so 6^2 or 6 x 6 =36
O(S)=36

probability = O(A) /O(S)
now just put the value into the formula and get the answer

Answer 13

i see 4 out of 36

Answer 14

2,5 and 2,6 are also greater than 6

Answer 15

so yes, 4/36 = 1/9

Answer 16

see now thats how you help some one

Answer 17

thank you

Answer 18

hasbees concept was sound, but just missing a few of the outcomes :)