Question

A quadratic equation is shown below:

x2 + 5x + 4 = 0

Part A: Describe the solution(s) to the equation by just determining radicand. Show your work.

Answer 1

so its asking you to consider the quadratic formula, but just the part that is the square root.

Answer 2

so just break it down to (x-?) (x+?)=0?
@amistre64

Answer 3

or it might be ++ instead of +-

Answer 4

its not asking for the solutions, but rather what kind of solutions we would expect given that the radicand (the discriminant) is positive, negative, or 0

Answer 5

recall the quad formula, given:

ax^2 + bx + c = 0

\[x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
now if:
b^2 - 4ac is positive, negative, or zero tells us the type of roots we will expect to get

Answer 6

so, 5^2 -4(1)(4) = 25-16

its positive, so what type of roots do we expect?

2 real and different
2 real and the same
or a complex, conjugate pair

Answer 7

2real and diffrent is what we will expect i think

Answer 8

thats correct

Answer 9

if its 0, then vertex + 0 is the same as vertex - 0

if its negative, then well, sqrt(-) has no real solutions

Answer 10

okay now u confused me