Mathematics
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OpenStudy (mony01):
What is the instantaneous velocity v of the particle at t=10.0s?
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OpenStudy (mony01):
OpenStudy (anonymous):
16
OpenStudy (mony01):
how you get that?
OpenStudy (anonymous):
at 10 s, it looks like the corresponding y value on the graph is about 6 seconds
OpenStudy (mony01):
so you just add those two?
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OpenStudy (anonymous):
|dw:1410051934620:dw|
OpenStudy (mony01):
i got it wrong
OpenStudy (anonymous):
Do you know how to read a graph?
OpenStudy (mony01):
isn't there a formula i have to use to solve it
OpenStudy (anonymous):
yes there is. Have you learned derivatives ?
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OpenStudy (mony01):
yea
OpenStudy (anonymous):
kk. So what you do is find an equation for tht line. u know how?
OpenStudy (mony01):
no
OpenStudy (anonymous):
get two points of from tht graph first and then find the slope
OpenStudy (anonymous):
do it now
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OpenStudy (mony01):
so like (0,10)
OpenStudy (anonymous):
yes and one more?
OpenStudy (mony01):
(25,25)???
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
so now u have two points, whats the slope?
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OpenStudy (mony01):
0.6
OpenStudy (anonymous):
so like the slope is 3/5
OpenStudy (anonymous):
3/5 = 0.6
OpenStudy (mony01):
yea
OpenStudy (anonymous):
ok so next use the slope intercept formula
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OpenStudy (anonymous):
y = mx + b, where m is the slope
OpenStudy (anonymous):
now find another point and that will be ur y and x in the formula
OpenStudy (anonymous):
plug everything in and solve fro b and then u have ur line equation
OpenStudy (anonymous):
what's the equation??
OpenStudy (mony01):
y=3/5(x)+10
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OpenStudy (anonymous):
ok very gooodd
OpenStudy (anonymous):
now whats the first derivative of that equationnn??
OpenStudy (mony01):
3/5
OpenStudy (anonymous):
3/5 m/s. that is ur answer
OpenStudy (anonymous):
because its linear, the velocity of the object moving is uniform meaning there is no acceleration or change n velocity. THE VELOCITY IS CONSTANT
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OpenStudy (mony01):
thanks