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Mathematics 22 Online
OpenStudy (mony01):

What is the instantaneous velocity v of the particle at t=10.0s?

OpenStudy (mony01):

OpenStudy (anonymous):

16

OpenStudy (mony01):

how you get that?

OpenStudy (anonymous):

at 10 s, it looks like the corresponding y value on the graph is about 6 seconds

OpenStudy (mony01):

so you just add those two?

OpenStudy (anonymous):

|dw:1410051934620:dw|

OpenStudy (mony01):

i got it wrong

OpenStudy (anonymous):

Do you know how to read a graph?

OpenStudy (mony01):

isn't there a formula i have to use to solve it

OpenStudy (anonymous):

yes there is. Have you learned derivatives ?

OpenStudy (mony01):

yea

OpenStudy (anonymous):

kk. So what you do is find an equation for tht line. u know how?

OpenStudy (mony01):

no

OpenStudy (anonymous):

get two points of from tht graph first and then find the slope

OpenStudy (anonymous):

do it now

OpenStudy (mony01):

so like (0,10)

OpenStudy (anonymous):

yes and one more?

OpenStudy (mony01):

(25,25)???

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

so now u have two points, whats the slope?

OpenStudy (mony01):

0.6

OpenStudy (anonymous):

so like the slope is 3/5

OpenStudy (anonymous):

3/5 = 0.6

OpenStudy (mony01):

yea

OpenStudy (anonymous):

ok so next use the slope intercept formula

OpenStudy (anonymous):

y = mx + b, where m is the slope

OpenStudy (anonymous):

now find another point and that will be ur y and x in the formula

OpenStudy (anonymous):

plug everything in and solve fro b and then u have ur line equation

OpenStudy (anonymous):

what's the equation??

OpenStudy (mony01):

y=3/5(x)+10

OpenStudy (anonymous):

ok very gooodd

OpenStudy (anonymous):

now whats the first derivative of that equationnn??

OpenStudy (mony01):

3/5

OpenStudy (anonymous):

3/5 m/s. that is ur answer

OpenStudy (anonymous):

because its linear, the velocity of the object moving is uniform meaning there is no acceleration or change n velocity. THE VELOCITY IS CONSTANT

OpenStudy (mony01):

thanks

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