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Mathematics 19 Online
OpenStudy (anonymous):

What function accurately represents the sine curve for red light? f(x) = sin pi over 640x f(x) = sin 640πx f(x) = sin 320πx f(x) = sin pi over 320x

OpenStudy (anonymous):

OpenStudy (jtvatsim):

OK, again a little intimidating... let's see if we can make sense of the graph.

OpenStudy (anonymous):

Okay :c

OpenStudy (jtvatsim):

It seems to me that y = 0 when x = 0, 320, and 640. Those are the three blue dots I think. Do you agree?

OpenStudy (anonymous):

Yes. ;o

OpenStudy (jtvatsim):

Alright, so here's a trick for multiple choice tests. Since we know how the graph should work, if we plug in x = 0, 320, and 640 into the correct answer it should give us a y = 0 each time!

OpenStudy (anonymous):

Okay, i see, i see.

OpenStudy (jtvatsim):

So does A make sense? How about x = 320? Does that give y = 0?

OpenStudy (anonymous):

i dont know how to solve it, but it doesnt look right.

OpenStudy (jtvatsim):

Just to make sure, what doesn't look right to you?

OpenStudy (anonymous):

Actually, no. Isnt it supposed to be in that form? like Pi over something.

OpenStudy (jtvatsim):

Alright... you are on a good track... let's carefully check each one.

OpenStudy (jtvatsim):

First, though, do you have sin(pi/2) memorized?

OpenStudy (anonymous):

(0,1)?

OpenStudy (jtvatsim):

Yes, that's right. So which one is sin(pi/2) is that 0 or 1?

OpenStudy (anonymous):

1.

OpenStudy (jtvatsim):

Good, that will be helpful in just a moment. :)

OpenStudy (jtvatsim):

Back to A, here's what I see when I plug in x = 320.

OpenStudy (jtvatsim):

sin(pi/640 * 320) = sin(320pi/640) = sin(pi/2) = 1 Does that make sense?

OpenStudy (anonymous):

OOO Yeah.

OpenStudy (jtvatsim):

But we know that when x = 320, the graph is SUPPOSED TO BE y = 0, so A is impossible.

OpenStudy (anonymous):

Yeah, i knew it didnt look right. :o

OpenStudy (jtvatsim):

Yep, your instinct was correct. But you also thought that the "form" looked right. Let's trust that intuition and look at D next, maybe that is our friend. :)

OpenStudy (anonymous):

Hopefully :c

OpenStudy (jtvatsim):

Alright, so we are considering sin(pi/320 * x) What do we get when x = 0? This is probably easy.

OpenStudy (anonymous):

0 ;o

OpenStudy (jtvatsim):

So far so good. Let's check when x = 320.

OpenStudy (jtvatsim):

I'm getting sin(pi) is that what you got?

OpenStudy (anonymous):

Uhh, Yeah. i did.

OpenStudy (jtvatsim):

OK, what is sin(pi) equal to?

OpenStudy (jtvatsim):

Alright, here's a bonus tip then, when the angle is pi, the coordinate is (-1, 0)

OpenStudy (anonymous):

OHH. Ohhkay. i see.

OpenStudy (jtvatsim):

So, is sin(pi) going to be -1 or 0?

OpenStudy (anonymous):

0

OpenStudy (jtvatsim):

Alright, I'm hoping this one works that's 2 out of 3 zeros so far! One more to check... x = 640.

OpenStudy (jtvatsim):

What do you see?

OpenStudy (anonymous):

oh, my calculator died o-o now i have to find batteries. .___.

OpenStudy (jtvatsim):

Well, you could probably use the computer calculator :)

OpenStudy (anonymous):

I Should. xD

OpenStudy (anonymous):

What are we plugging 640 in?

OpenStudy (jtvatsim):

D, so sin(pi/320 * x)

OpenStudy (anonymous):

2?

OpenStudy (jtvatsim):

well, sin(2pi) is what you mean right?

OpenStudy (anonymous):

Yeah.

OpenStudy (jtvatsim):

Cool, so we have to have that memorized or calculate it

OpenStudy (jtvatsim):

sin(2pi) corresponds to the angle 2 pi, which has the coordinate (1, 0)

OpenStudy (anonymous):

OH. So D's the answer? ;o

OpenStudy (jtvatsim):

It appears to be the case.

OpenStudy (jtvatsim):

The others also give you y = 0 for x = 0, 320, 640, but they are the wrong form... they will compress the graph since they are multiplying instead of stretching the graph like we want

OpenStudy (anonymous):

OH YAY

OpenStudy (jtvatsim):

YAHOO!

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