Question

The equation of a circle is (x + 3)^2 + (y + 5)^2 = 8. Determine the coordinates of the center of the circle.

Answer 1

for
\(\Large (x-h)^2+(y-k)^2 =r^2 \)
the center is h,k

so how about
\(\Large (x+3)^2+(y+5)^2 =8 \)

Answer 2

compare those 2 equations

Answer 3

The x coordinate is the -h value, while the y coordinate is the -k value.
\[(x+3)^2+(y+5)^2=8\]
In this case, the h value is 3 and the k value is 5
Since the x-coordinate is -h:
\[x=-h\]
\[x=-1*3\]
\[x=-3\]
This is the same with the y-coordinate
\[y=-k\]
\[y=-1*5\]
\[y=-5\]

Answer 4

I got (3,5)

Answer 5

I was late.

Answer 6

Remember, the coordinates are the NEGATIVE of the h, k value. See above