The equation of a circle is (x + 3)^2 + (y + 5)^2 = 8. Determine the coordinates of the center of the circle.

Question

The equation of a circle is (x + 3)^2 + (y + 5)^2 = 8.  Determine the coordinates of the center of the circle.

hartnn · Answer

for 
$\Large (x-h)^2+(y-k)^2 =r^2 $
the center is h,k

so how about 
$\Large (x+3)^2+(y+5)^2 =8 $

hartnn · Answer

compare those 2 equations

ahsome · Answer

The x coordinate is the -h value, while the y coordinate is the -k value.
$$(x+3)^2+(y+5)^2=8$$
In this case, the h value is 3 and the k value is 5
Since the x-coordinate is -h:
$$x=-h$$
$$x=-1*3$$
$$x=-3$$
This is the same with the y-coordinate
$$y=-k$$
$$y=-1*5$$
$$y=-5$$

anonymous · Answer

I got (3,5)

anonymous · Answer

I was late.

ahsome · Answer

Remember, the coordinates are the NEGATIVE of the h, k value. See above