Question

Please help!
A solution was prepared by dissolving 177 mg of potassium sulfate (K2SO4, MW = 174.24 g/mol) in 775 mL of water. Calculate the following:
a) Moles of K2SO4
b)Millimoles of K2SO4
c)Molarity of K2SO4, K+, SO4(2-)
d)ppm of K2SO4
e)%(w/v) K2SO4
f)pK+
g)pSO4(2-)

Answer 1

So first convert mg to g.

a) \(\sf moles=\dfrac{mass~(in~g)}{Molar ~mass}\)

b) 1 mole = 1000 millimoles

c) \(\sf Molarity=\dfrac{moles~of~solute}{L~of ~solution}\)

d) 1ppm = 1 mg/L

do these first