Question

how do i answer 2x-3=sqrroot30-7x

Answer 1

2x-3=\[\sqrt{30-7x}\]

Answer 2

is this

\[2x-3=\sqrt{30-7x}\]

OR
\[2x-3=\sqrt{30} - 7x\]

Answer 3

the first one

Answer 4

ok soz - I saw your answer after I posted!

square both sides of the equation

Answer 5

its okay

Answer 6

\[(2x-3)^{2}=(\sqrt{30-7x})^{2}\]

Answer 7

so the square root cancels

Answer 8

yes

Answer 9

and 2x-3 turns into 4x^2-12x+9

Answer 10

yes

Then collect all terms onto 1 side (other side =0)
You then have a quadratic

Answer 11

okay so ima have 0=4x^2+5x-21

Answer 12

not sure that is correct

4x^2-12x+7x+9-30

Answer 13

so 4x^2-5x-21 ???

Answer 14

yes

It doesn't factorise - so use formula

Answer 15

what do i do next??

Answer 16

use quadratic formula to solve the equation

4x^2-5x-21=0

(ax^2+bx+c=0)

x=(-b +/- sqrt (b^2-4ac))/2a

Answer 17

i forgot wAT to do after this part
5x+\[\sqrt{361}\] over 8