Question

Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400mi\;{\rm mi} away. He travels at a steady 50mph\;{\rm mph} . Beth leaves Los Angeles at 9:00 a.m. and drives a steady 60mph\;{\rm mph} .B

How long does the first to arrive have to wait for the second?

Answer 1

help

Answer 2

\;{\rm mi}
what is this?

Answer 3

I don't know it to hard of a question

Answer 4

can you do a snapshot of the problem

Answer 5

oh yeah it just mph

Answer 6

no rm

Answer 7

it just mi and mph

Answer 8

do you get it

Answer 9

can get the screenshot dude

Answer 10

okay so!
we need to know how many our each will drive to san francisco
the equation is like this v=d/t
so t=d/v
we are given the distance btw los and san to be 400
v=50 for alan
so for Alan we have
t=400/50=8 hour
so if he started at 8:00 am he will arrive at 4:00pm

Answer 11

bent is the one that arrive first

Answer 12

for beth
t=400/60=6.66 hour that is 6hour 40min
so if he started at 9:00am he will arrive at 3:40 pm

Answer 13

yeah so he will arrive 20 minutes before Alan

Answer 14

Do you get the process here?

Answer 15

yeah but how much times the another one have to what for the other one

Answer 16

is it 20 min

Answer 17

yes 20 minute since the first arrives at 3.40
the second 4:00
so 20 minute difference

Answer 18

can you help my on a another one just one more