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(Solve algebraically) One number is 3 more than twice the other number. If the sum of the two numbers is 21, find the two numbers. (Use a comma to separate answers as needed)
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So in this problem you are given two unknowns s o you will need 2 equations to solve
one number we will call x the other number we will call y
x = 3+2y and x+y=21
So we can use x=3+2y and plug it into the x+y =21 equation
(3+2y)+y = 21
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3+3y=21 3y=18 y=6
And now we have y so just plug it into the x+y= 21 formula again to find x :)
got it! thank you very much!
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