an empty propane tank dropped from a hot air balloon hits the ground with a speed of 148.3 m/s. From what height was the tank released?

Question

samsan9 · Answer

@fateal

fateal · Answer

ok so this is the formla....
 t=d/v distance over velocity...
will i think that we need to adjust it tho o.e
do  u have one for this question?

fateal · Answer

do u have more info about this question?

samsan9 · Answer

tbh idk one but i am looking through my equation sheet

fateal · Answer

oh ok...cus that will be easier :)

samsan9 · Answer

h=1/2gt^2

samsan9 · Answer

i know g=9.8

fateal · Answer

so its going to be h=1/2 (9.8) 148.3 ^ 2
does ^ mean multiply ?

samsan9 · Answer

it means that its squared

fateal · Answer

oh ok... so did i plug them right?

samsan9 · Answer

hold up let me try it

fateal · Answer

ok

fateal · Answer

i got this: 107765.161 so i dont think so??

foolaroundmath · Answer

Using $v_f^2 - v_i^2 = 2as $ and taking downward direction to be positive,

Assume the tank was released from rest (i.e. $v_i = 0$)
$ s = \text{height}, \;\;\; v_f = \text{final speed} = 148.3, \; \;\;\;a = g = 9.8$

Plug it in, $\displaystyle s = \frac{v^2}{2g} = \frac{148.3^2}{2\times9.8} = 1122.08\text{ m}$

samsan9 · Answer

um ill just put both answers and ask if my friends got it XD

fateal · Answer

oh ok x3 i was trying to use https://www.mathway.com/ but ok

samsan9 · Answer

lol thank you guys

fateal · Answer

np x3