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OpenStudy (samsan9):
a bullet is fired directly upward with a speed of 300 m/s. How far above the ground will the bullet be in 65 seconds?
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OpenStudy (samsan9):
what do you think?
OpenStudy (samsan9):
what sucks even more is that i have 12 questions left people :(
OpenStudy (anonymous):
well use this formula,
\[v=ut+1/2at^2\]
OpenStudy (samsan9):
ok well i know that u could equal zero
OpenStudy (anonymous):
zero??? what equal to 0? O.o
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OpenStudy (anonymous):
see u will get as
\[(330m/s)(65s)+1/2(-9.8m/s^2)(65s)^2\]
calculate @samsan9
OpenStudy (anonymous):
did you?? i got the answer :P
OpenStudy (samsan9):
i got 41.85 m/s
OpenStudy (anonymous):
did you make one correction....in above formula i wrote 330m/s instead of 300m/s.
OpenStudy (samsan9):
um i got a negative answer but yeah i used the the 330
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OpenStudy (anonymous):
yeah for sure u will get negative because bullet is fired upwards against the gravity....
OpenStudy (anonymous):
i got 1202.5m
OpenStudy (samsan9):
i got the same thing lol i thought a negative was bad XD thank you
OpenStudy (anonymous):
haha!! lol nopes that's correct :)
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