Part I: Titration with an indicator Insert a complete data table, including appropriate significant figures and units, in the space below. Be sure to include all trials that were completed in part I. Also include any observations that you made over the course of part I. (5 points) Volume of HCl 20.0 mL Initial volume of NaOH in buret 50.0 mL Final volume of NaOH in buret 34.0 mL Trial 2 (If needed) Volume of HCl 20.0 mL Initial volume of NaOH in buret 50.0 mL Final volume of NaOH in buret 34.0 mL Trial 3 (If needed) Volum
I did all of the lab stuff I just can't do the calculations that are in the attached file
@k142
@ankit042@thomaster @rvc @faRiz @midhun.madhu1987 @Love.Kat123
You know how much NaOH you needed to reach the equivalence point, and you know its concentration so it is a simple matter of: 1. Determine volume of NaOH needed to reach equivalence point Final buret reading - initial reading = volume of NaOH needed Convert volume from mL to L 1000mL = 1L (you can just multiply mL by (1/1000) to get to liters) 2. Find moles of NaOH needed to reach equivalence point (I dont see a concentration but I will assume it is in molarity) Molarity = Moles/Volume (in litres) solve for moles of NaOH 3. Use the reaction formula: NaOH + HCl -> H2O + NaCl No balancing required it is 1 to 1 Use the reaction formula to find moles of HCl Since it is 1 to 1, Moles of NaOH = Moles of HCl 4. Take the formula: Molarity = Moles/Volume (Litres) Solve for Molarity and you are done the problem.
It pretty much explains this in your lab
Sorry for step 4 Volume in the formula will be the original volume of HCl solution
Make sure it is in litres
By equivalence point I mean the point at which the indicator changed to the colour desired
If you have any questions feel free to ask
Also for step 2 the volume you use in the formula will be the volume you determined in step 1
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