Find the GCF. A. 28a3b3c4 The three's and the four are small here. B. 14 C. 14abc D. 28abc
The equation is above.
can you find the GCF for 14 and 28?
GCF is the biggest number that divides evenly into both.
7? @phi
7 is a common factor, but not the biggest. how about 14?
14 divides into 14 and into 28 evenly, right?
That would work!
so 14 is part of the answer. any idea what the GCF is for a and a*a ?
That's where I get lost! lol
with a letter you don't have a lot of options. the only thing we know that will divide evenly into "a" is itself.
and what is A. standing for?
a is a number. But we know this: a/a = 1 (anything divided by itself is 1) which means a divides evenly into a. The next question is , does a divide evenly into a*a ?
Yeah I think it would.
you can re-write it like this \[ \frac{a\cdot a}{a} = \frac{a}{a} \cdot a\] now use a/a= 1 to say \[ 1 \cdot a = a \] in other words, a*a/a = a with NO remainder. (i.e. divides evenly) so a divides evenly into a and into a*a and because there is no other thing (except 1) that divides into a (as far as we know), a is the greatest common factor of a and a*a
btw, \[ a \cdot a= a^2\] so we found the GCF of \( a \text{ and } a^2\)
so far the GCF is 14a any idea what the GCF of b and b*b is ?
7?
the gcf of a letter b and b*b is not a fixed number. It will be a letter
b?
LOL Im sorry... I'm horible at these thing's.
yes, b is the only thing other than 1 that evenly divides into both b and b*b
YAY!
If you are lost, it's because there is an idea you are missing. Once you get the idea, it makes sense.
now the gcf of c and c*c*c ?
C.!
Option C. is looking promising...
yes, and all together we get 14abc
WOW!! Thanks for working with me man! I really appreciate it!!
*handshake*
if you have the idea, then what is the gcf of a*a and a*a*a ? any idea ?
A.!
a is a factor, but we can do more.
A and A???
\[ \frac{a\cdot a}{a\cdot a} = \frac{a}{a} \cdot \frac{a}{a} = 1\] in other words a*a divides evenly into a*a
yes, but I would say A TIMES A (not A and A)
OOOOhhh alright! Cool!
and \[ \frac{a\cdot a\cdot a}{a\cdot a} = a \] so a*a is the gcf of a*a and a*a*a
or, using exponents the gcf of \( a^2 \) and \(a^3\) is \( a^2 \)
Okay! Wow. Thanks again for all your brainpower! =)
Join our real-time social learning platform and learn together with your friends!