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Physics 21 Online
OpenStudy (abmon98):

Two particles A and B are simultaneously projected from the same point on a horizontal plane. The initial velocity of A is 15m/s at 25 degree to the horizontal and the initial velocity of B is 15m/s at 65 degree to the horizontal. a)Construct a diagram showing paths of both particles until they strike the horizontal plane. b) from your diagram estimate the time each particle is in the air c) calculate these times correct to 3 s.f

OpenStudy (abmon98):

Particle A x horizontal velocity of magnitude=vcosѲ=15cos25=13.6 y vertical velocity of magnitude=vsinѲ=15sin25=6.35 Particle B x horizontal velocity of magnitude=vcosѲ=15cos65=6.35 y vertical velocity of magnitude=vsinѲ=15sin65=13.6

OpenStudy (anonymous):

it is b i think

OpenStudy (abmon98):

thats not a multiple question @mistyrforrest

OpenStudy (abmon98):

multiple choice**

OpenStudy (anonymous):

: )

OpenStudy (abmon98):

can i ask you a question both will travel the same ditance. when applying pythageorn theorm both particles will exert the same velocity and eventually the same distance.

OpenStudy (anonymous):

your velocity components look correct to me i'm not sure if they will travel the same distance, maybe not i'm not sure what your last statement means, but don't worry about that

OpenStudy (anonymous):

what you have to do is pick a particle, let's start with A then focus your mind on the vertical motion and with v = u-gt applied to the vertical motion you can work out the time of flight

OpenStudy (abmon98):

v=6.35-10t

OpenStudy (anonymous):

yes, and we know v as well

OpenStudy (anonymous):

you remember, it will have the same speed coming down at a particular height, as it had on the way up, just going in the opposite direction

OpenStudy (anonymous):

so v = -6.35

OpenStudy (anonymous):

when it hits the ground again

OpenStudy (abmon98):

yes you are right :),

OpenStudy (abmon98):

-6.35-6.35/-10=t t=1.27s

OpenStudy (anonymous):

yes, that looks right

OpenStudy (anonymous):

and now because you know the horizontal speed of particle A you can figure out how far it went horizontally in that time

OpenStudy (abmon98):

s=ut s=13.6*1.27=17.3

OpenStudy (anonymous):

you got it : )

OpenStudy (abmon98):

same thing to particle B

OpenStudy (anonymous):

now just go through the same procedure for particle B I think you were right when you suspected they both go the same distance, i think you will find the same distance for particle B, i wasn't sure at first

OpenStudy (anonymous):

yes

OpenStudy (abmon98):

-13.6-13.6/-10=2.72 s s=6.32*2.72=17.12 thank you so much :D

OpenStudy (anonymous):

well done - problem solved

OpenStudy (anonymous):

although we skipped the estimating part and remember the question asked for 3 significant figures in your answers to part c : )

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