completer chemical equations to describe the ionization or dissociation behavior of all the sloutes below ( example: NaCl (s) arrow to Na^+ (aq) +Cl^- (aq) a) Ioniztion of covalent acids, bases and other HC2H3O2 (aq)
I will provide more solutes later
but please can you help me do this one first
I'm not sure what they're asking here.. Do they want to break it down, name it, etc?
HC2H3O(AQ) H2S04(aq)-------2 steps NH3(aq) HCl(aq) HgCl2(aq)
completer chemical equations to describe the ionization or dissociation behavior of all the sloutes below ( example: NaCl (s) arrow to Na^+ (aq) +Cl^- (aq) a) Ioniztion of covalent acids, bases and other
Base: proton acceptor NH3 (aq) + H2O (l) ⇄NH4+(aq) + OH – (aq)
An Arrhenius acid is shown when the presence of \(\textsf{H}\)\(_3\)\(\textsf{O}\)+ ions. In the case of \(\textsf{HC}\)\(_2\)\(\textsf{H}\)\(_3\)\(\textsf{O}\)\(_2\) the problem is that the structure of the molecule is obscured by this writing of the formula. It's an acetic acid that can be written as: \(\textsf{CH}\)\(_3\)\(\textsf{COOH} \) where \(\textsf{COOH}\) is the carboxyl group that identifies a type of organic acid. When the acid dissociates, the COOH group loses the last H atom \(\textsf{CH}\)\(_3\)\(\textsf{COOH(aq)}\) <--------> \(\textsf{CH}\)\(_3\)\(\textsf{COO-(aq) + H+(aq)}\) Yahoo!
there is a presence of*
Acid: proton donor HCl (aq) + H2O (l)-->H3O+(aq) + Cl –(aq)
ok and the other 3 HC2H3O2(AQ) H2S04(aq)-------2 steps HgCl2(aq)
there is part B also Dissociation of Basics Hydroxides and Other Ionic Compounds Basic Hydroxides: NaOH(aq) Ba(OH)2 (aq) Other Ionic Compounds: NaCl (aq) Na3PO4(aq)
H2SO4 is a strong acid, H2SO4 can produce two H+ ions per molecule when dissolved in water. However The ionization of polyprotic acids occurs in steps, with the molecule losing one proton at a time H2SO4(aq)+H2O(l)+⇌H3O+(aq) + HSO4-(aq) HSO4-(aq) +H2O(l)⇌H3O+(aq) + SO42-(aq)
how about HC2H3O(AQ) HgCl2(aq)
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