Question

PLEASE HELP I know how you are supposed to do it but I cant understand this one:(
Solve the equation. Check for extraneous solutions.
9|9 – 8x| = 2x + 3

Answer 1

Divide by 9
9-8x= 2x+ 1/3 or 9-8x= -(2x+ 1/3)
Add 8x both sides
Minus 1/3 both sides

Answer 2

thats how im trying to do it but idk if thats what the nine needs to do

Answer 3

when you divide by 9 on both sides , the right side becomes
\[ \frac{2x +3}{9} \]
which can also be written as
\[ \frac{2}{9}x + \frac{1}{3} \]

Answer 4

the rest looks ok. For the positive equation, we would have
\[ 9 - 8x = \frac{2}{9}x + \frac{1}{3}
\\ 9 = 8x+\frac{2}{9}x + \frac{1}{3} \\
9- \frac{1}{3} = 8x+\frac{2}{9}x
\]
after combining the fractions
\[ \frac{26}{3} = \frac{74}{9}x \]
and
\[ x = \frac{\cancel{9}3}{\cancel{74}37} \cdot \frac{\cancel{26}13}{\cancel{3}} =\frac{39}{37}\]

Answer 5

@phi thanks:)