Why cant x^2+81 be factored?
with real numbers, several reasons one is that \[x^2+81\geq 81\] so it is never zero if you could factor it, it would have zeros
not sure what "reason" means in this context, but you can always factor the DIFFERRENCE of two squares, but not the SUM
of two square
what do you mean by difference of two squares but not the sum
Just simply use the quadratic equation
example (x^2-4) and (X^2+4) difference and sum
@satellite73 are you saying you can only factor it if its a minus sign and not adding sign?
is the example given to you was (x^2-81) it could be factored because is a difference of squares but not (x^2+81) since is a sum :)
ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhh that makes a lot of sense not but what would it be if it was x^2-81?
(x+9) (x-9)?
(x+9)(x-9) = x^2-9x+9x-81... 9x-9x =0 and cancel leaving you with x^2-81 :)
thanks that helps a lot!
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