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OpenStudy (anonymous):
Why cant x^2+81 be factored?
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OpenStudy (anonymous):
with real numbers, several reasons
one is that \[x^2+81\geq 81\] so it is never zero
if you could factor it, it would have zeros
OpenStudy (anonymous):
not sure what "reason" means in this context, but you can always factor the DIFFERRENCE of two squares, but not the SUM
OpenStudy (anonymous):
of two square
OpenStudy (anonymous):
what do you mean by difference of two squares but not the sum
OpenStudy (anonymous):
Just simply use the quadratic equation
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OpenStudy (kl0723):
example (x^2-4) and (X^2+4) difference and sum
OpenStudy (anonymous):
@satellite73 are you saying you can only factor it if its a minus sign and not adding sign?
OpenStudy (kl0723):
is the example given to you was (x^2-81) it could be factored because is a difference of squares but not (x^2+81) since is a sum :)
OpenStudy (anonymous):
ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhh that makes a lot of sense not but what would it be if it was x^2-81?
OpenStudy (anonymous):
(x+9) (x-9)?
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OpenStudy (kl0723):
(x+9)(x-9) = x^2-9x+9x-81... 9x-9x =0 and cancel leaving you with x^2-81 :)
OpenStudy (anonymous):
thanks that helps a lot!
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