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OpenStudy (anonymous):
Use elimination to solve the system of equations. Enter your answer as an ordered pair; example: (4, -5)
{12x+y=4-2x−2y=-6
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OpenStudy (anonymous):
no, maybe
\[12x+y=4\\
-2x-2y=-6\]
OpenStudy (anonymous):
how fast you want to do it?
OpenStudy (anonymous):
im confused
OpenStudy (anonymous):
we didn't do anything yet, i just wrote down what i thought the question was
OpenStudy (anonymous):
lol so you really must be confused !!
lets go slow
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OpenStudy (anonymous):
i wrote it wrong its 1/2x + y= 4
-2x-2y=-6
OpenStudy (anonymous):
oooh ok
lets get rid of annoying fraction right away by multiplying everything in the first equation
\[\frac{1}{2}x+y=4\] by \(4\)
OpenStudy (anonymous):
we are going to multiply each term by \(4\) and get
\[2x+4y=16\] for the first one
clear or no?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok now we line them up
\[2x+4y=16\\
-2x-2y=-6\]
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OpenStudy (anonymous):
add in a column, and a miracle will occur,
since \(2x-2x=0\) you end up with
\[2y=10\] when you add
OpenStudy (anonymous):
ok to that step or no?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok then if \(2y=10\) is is pretty clear what \(y\) is yes?
OpenStudy (anonymous):
please say "yes" (i hope)
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OpenStudy (anonymous):
5
OpenStudy (anonymous):
mm
OpenStudy (anonymous):
thanks
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