Use elimination to solve the system of equations. Enter your answer as an ordered pair; example: (4, -5) {12x+y=4-2x−2y=-6
no, maybe \[12x+y=4\\ -2x-2y=-6\]
how fast you want to do it?
im confused
we didn't do anything yet, i just wrote down what i thought the question was
lol so you really must be confused !! lets go slow
i wrote it wrong its 1/2x + y= 4 -2x-2y=-6
oooh ok lets get rid of annoying fraction right away by multiplying everything in the first equation \[\frac{1}{2}x+y=4\] by \(4\)
we are going to multiply each term by \(4\) and get \[2x+4y=16\] for the first one clear or no?
yes
ok now we line them up \[2x+4y=16\\ -2x-2y=-6\]
add in a column, and a miracle will occur, since \(2x-2x=0\) you end up with \[2y=10\] when you add
ok to that step or no?
yes
ok then if \(2y=10\) is is pretty clear what \(y\) is yes?
please say "yes" (i hope)
5
mm
thanks
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