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Find the sum of the infinite series 1/3+4/9+16/27+64/81+... if it exists
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well it would appear that the common ratio is \[r = \frac{4}{3}\] since r > 1 then the series will diverge...
what do u mean if it exists?
well if the series has a value of r such that -1 < r < 1 then the series converges and you can find an infinite sum
first find q. \[q=\frac{ 4 }{ 9 }\div \frac{ 1 }{ 3 }=\frac{ 4 }{ 3 }\] when q>1 we use this formula \[s _{n}=\frac{ q^n-1}{ q-1 }\] but we don't have n so we can't find the sum.
This is an infinite series. n -> infinity.
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Since this is a divergent series there is no sum.
thank you
glad to help
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