Question

problem on collisions

Answer 1

A body of mass m moving with a velocity v is approaching a second object of same mass but at rest. The K.E of two objects as viewed from the center of mass is???

Answer 2

\[1/8mv^2\]

Answer 3

\[mv^2/8\]

Answer 4

@aryandecoolest

Answer 5

it's \[mv^2/4\]

Answer 6

it's the total kinetic energy but the kinetic energy of individual body is \[mv^2/8\]
@aryandecoolest

Answer 7

yeah the same...i asked for total K.E....

Answer 8

thank you @aryandecoolest

Answer 9

How did you get total K.E as mv^2/8.
Can you please explain ?
@tony115 and @aryandecoolest

Answer 10

from the center of mass, each body will appear to be moving towards that center at v/2.
KE = ½mv²

so the center of mass will see two masses each with a KE of ½m(v/2)²

total kinetic energy will be

2KE = (2) ½m(v/2)²
KE = ¼mv²