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how to solve: lim x->2 (x^2-4x+4)/(x-2)
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you use the distributive property.
what math is this
limits and continuity
factor the numerator then simpify
Very SImple.. \[\lim_{x->2}\frac{ (x-2)^2 }{ (x-2) }=> \lim_{x->2}(x-2) = 0\] Therefore the limit doesn't exist because If x is near to 2 but a little higher, both these are positive so you get +∞ And, if x is close to 2 but a little lower, the top is positive but the bottom is negative so you get - ∞
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yes i agree
+??? = + infinity -??? = -Infinity
thanks, thats what I started doing, but did not like the 0 ;)
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