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Mathematics 20 Online
OpenStudy (anonymous):

Help plzzzZzZ!!

Elsa213 (elsa213):

question?

OpenStudy (lunymoony):

Question plzzzzZzZ!!

OpenStudy (anonymous):

Simplify the following radical expression: \[4\sqrt{32}\]

OpenStudy (anonymous):

it would be better if some1 could expain me the whole process... Thanks

OpenStudy (anonymous):

4 * 32 Squared?

OpenStudy (anonymous):

well let's see the four would change to 2 and the 32 would be 16 because

OpenStudy (dangerousjesse):

Simplify radicals. \(\sqrt{32} = \sqrt{2^5} = 2^2 \sqrt2\): \(4×2^2 \sqrt2\) Evaluate \(2^2.\) \(2^2 = 4:\) \(4×4 \sqrt 2\) Multiply 4 and 4 together. \(4×4 = 16:\)

undeadknight26 (undeadknight26):

^ what they said.

OpenStudy (dangerousjesse):

@XVasHappeninZen Numbers don't just "change". You need to explain how to get that.

OpenStudy (anonymous):

first we know that we multiply so 32 equals √2x4

OpenStudy (anonymous):

Next you get √2x4x4

OpenStudy (anonymous):

here is my question is it \[\huge 4\sqrt{32}\] or is it \[\huge \sqrt[4]{32}\] makes a huge difference

OpenStudy (anonymous):

so it is √2x16

OpenStudy (anonymous):

Hope you understand

OpenStudy (anonymous):

the second one @satellite73

OpenStudy (anonymous):

the boxes are the squared sign

OpenStudy (anonymous):

its \[^4\sqrt{32}\]

OpenStudy (dangerousjesse):

I wish you would have told us that earlier..

OpenStudy (anonymous):

i just answered -_-

OpenStudy (anonymous):

My book says the answer is \[2^4\sqrt{2}\]

OpenStudy (anonymous):

lol then since \[2^4=16\] and \[32=16\times 2\] you have \[\sqrt[4]{32}=\sqrt[4]{16\times 2}=\sqrt[4]{16}\sqrt[4]{2}=2\sqrt[4]{2}\]

OpenStudy (anonymous):

yes you book answer is right

OpenStudy (anonymous):

it means two times the fourth root of two

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