Help plzzzZzZ!!
question?
Question plzzzzZzZ!!
Simplify the following radical expression: \[4\sqrt{32}\]
it would be better if some1 could expain me the whole process... Thanks
4 * 32 Squared?
well let's see the four would change to 2 and the 32 would be 16 because
Simplify radicals. \(\sqrt{32} = \sqrt{2^5} = 2^2 \sqrt2\): \(4×2^2 \sqrt2\) Evaluate \(2^2.\) \(2^2 = 4:\) \(4×4 \sqrt 2\) Multiply 4 and 4 together. \(4×4 = 16:\)
^ what they said.
@XVasHappeninZen Numbers don't just "change". You need to explain how to get that.
first we know that we multiply so 32 equals √2x4
Next you get √2x4x4
here is my question is it \[\huge 4\sqrt{32}\] or is it \[\huge \sqrt[4]{32}\] makes a huge difference
so it is √2x16
Hope you understand
the second one @satellite73
the boxes are the squared sign
its \[^4\sqrt{32}\]
I wish you would have told us that earlier..
i just answered -_-
My book says the answer is \[2^4\sqrt{2}\]
lol then since \[2^4=16\] and \[32=16\times 2\] you have \[\sqrt[4]{32}=\sqrt[4]{16\times 2}=\sqrt[4]{16}\sqrt[4]{2}=2\sqrt[4]{2}\]
yes you book answer is right
it means two times the fourth root of two
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