Question

9|9-8x|=2x+3

Answer 1

Divide both sides by a constant to simplify the equation.
Divide both sides by 9:
\(abs(9-8 x) = \frac{1}{9} (2 x+3)\)
Eliminate the absolute value.
Split the equation into two possible cases:
\(9-8 x = \frac{1}{9} (2 x+3)\) or \(9-8 x = \frac{1}{9} (-3-2 x)\)
Look at the first equation: Write the linear polynomial on the right hand side in standard form.
Expand out terms of the right hand side:
\(9-8 x = \frac{2 x}{9}+\frac{1}{3}\) or \(9-8 x = \frac{1}{9} (-3-2 x)\)
Isolate x to the left hand side.
Subtract \(\frac{2 x}{9}+9\) from both sides:
-\(\frac{74 x}{9} = -\frac{26}{3}\) or \(9-8 x = \frac{1}{9} (-3-2 x)\)
Solve for x.
Multiply both sides by \(\frac{-9}{74}\):
\(x = \frac{39}{37}\) or \(9-8 x = \frac{1}{9} (-3-2 x)\)
Write the linear polynomial on the right hand side in standard form.
Expand out terms of the right hand side:
\(x = \frac{39}{37}\) or \(9-8 x = \frac{-1}{3}-\frac{2 x}{9}\)
Isolate x to the left hand side.
Subtract \(9-\frac{2 x}{9}\) from both sides:
\(x = \frac{39}{37}\) or \(-\frac{70 x}{9} = \frac{-28}{3}\)
Solve for x.
Multiply both sides by \(\frac{-9}{70}\):

Answer 2

Which leaves you with...?

Answer 3

I'm not really sure, don't you do
70x/9=-28/3
x-9/70 x -9/70
do you cross multiply