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AB has endpoints A(3,6) and B(9, -2) and midpoint M. What is AM?
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First find M: \(M = \left(\dfrac{x_1 + x_2}{2}, \dfrac{y_1 + y_2}{2}\right)\)
M= (6,2) right?
In this case \((x_1,y_1) = (3,6)\) \((x_2, y_2) = (9,-2)\)
To find the length of \(\overline{AM}\), use the distance formula: \(AM = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
In this case \((x_1, y_1) = (3,6)\) \((x_2, y_2) = (6,2)\)
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does it equal 5?
Correct
thank you
yw
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