3a^3+a^2-2a
What exactly are you doing with this? Because you can factor out an "a" and then factor the rest since its essentially in quadratic form.
Yes I am trying to factor this @Johnbc
What exactly are you doing with this? Because you can factor out an "a" and then factor the rest since it WILL BE essentially in quadratic form
You can start by factoring out the "a" term so that you get?
Hint: take out one a (3a^2+a-2) continue to factor ;)
Here is an example that might help you Simplifying (2a + 6 * 2)(3a + 3) + a Multiply 6 * 2 (2a + 12)(3a + 3) + a Reorder the terms: (12 + 2a)(3a + 3) + a Reorder the terms: (12 + 2a)(3 + 3a) + a Multiply (12 + 2a) * (3 + 3a) (12(3 + 3a) + 2a * (3 + 3a)) + a ((3 * 12 + 3a * 12) + 2a * (3 + 3a)) + a ((36 + 36a) + 2a * (3 + 3a)) + a (36 + 36a + (3 * 2a + 3a * 2a)) + a (36 + 36a + (6a + 6a2)) + a Combine like terms: 36a + 6a = 42a (36 + 42a + 6a2) + a Reorder the terms: 36 + 42a + a + 6a2 Combine like terms: 42a + a = 43a 36 + 43a + 6a2
Im a little confused... If I took out the "a" wouldn't it be (3a^3+a2-2)? @kl0723
no... remove an a from the 3a^3 and you're left with 3a^2... then from a^2 and you're left with only a and from 2a and you;re left with 2 ;)
Would it be a(3a+1)-2 ? @kl0723 I am probably wrong lol
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