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Let s(t) = 9t^2 + 2t + 70 be the position, in miles, of a car driving on a straight road at time t, in hours. The car's velocity at any time t is given by v(t) = 18t + 2. Find the car's position when the car is going 74 mph.
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so let v(t) = 74 and solve for t when you get t, substitute it into the position equation.
ok. let me try
so i got the answer as 16018742
do i leave it like that?
well start with v(t) 74 = 18t + 2 can you solve for t...?
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its 4
222
thats correct now subsitute it into position \[s(4) = 9\times(4)^2 + 2\times 9 + 70\]
that's correct... the car is 222 miles to the right of its starting point
ok
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ooops middle term should be 2 x 4... sorry about that not 2 x 9
ok
thanks
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