Question

Chap 5 (EXE 5.4)
5)a)

Answer 1

@rational

Answer 2

http://prntscr.com/4l7kql

Answer 3

You're given :
gradient of " `xy = c^2`" at a point `(ct, c/t)` is `-1/t^2`

Answer 4

5a :

xy = 9

Answer 5

compare this with the given form
`c = ?`

Answer 6

3 ?

Answer 7

yes what about t ?

Answer 8

I'm nt sure
Actually, t refers to parameter ?

Answer 9

t is t itself,
so the gradient would be simply `-1/t^2`

Answer 10

lets do 5b

Answer 11

ok

Answer 12

5b :

xy = 4

Answer 13

`c = ?`

Answer 14

3 and 4/3 ?

Answer 15

c = ?

Answer 16

4^2 ?

Answer 17

xy = 4

xy = 2^2

c = 2

Answer 18

next look at given point :

(3, 4/3)

compare this with

(ct, c/t)

Answer 19

ct = 3

t = 3/c
= 3/2

Answer 20

yes ?

Answer 21

ok

Answer 22

so the gradient would be ?

Answer 23

gradient = -1/t^2
= ?

Answer 24

I really don't know..

Answer 25

plugin the value of t here

Answer 26

t = 3/2

Answer 27

gradient=