Question

If x,y are the integral sollutions of
2x^2 -3xy - 2y^2 = 7 , then mod(x+y) =

Answer 1

I would start by trying to factor the left quadratic

Answer 2

How to do that

Answer 3

its just a quadratic, split the middle term

Answer 4

-4+1 = -3
-4*1 = -4

Answer 5

2x^2 -3xy - 2y^2 = 7

2x^2 - 4xy - xy - 2y^2 = 7

group terms and factor

Answer 6

was doing my net disconnected

Answer 7

2x(x-2y)-y(x-2y)
(2x-y)(x-2y)

Answer 8

2x^2 - 4xy + xy - 2y^2 = 7

2x(x-2y) + y(x-2y) = 7

(x-2y)(2x+y) = 7

Answer 9

the only factors that multiply to 7 are : {1, 7} or {-1, -7}

Answer 10

ya sry

Answer 11

i think i got the next step