Question

@ganeshie8
factoring:
when grouping 24xy + 64x^2 + 42y + 112x,
i get (8x+14) and (4x+7) after factoring with 8x and 6y.

Answer 1

64x^2 + 112x + 24xy + 42y

8x(8x+14) + 6y(4x + 7)

Answer 2

Notice that you can still factor a 2 from first binomial

Answer 3

64x^2 + 112x + 24xy + 42y

8x(8x+14) + 6y(4x + 7)

16x(4x+7) + 6y(4x+7)

Answer 4

now factor the GCF 4x+7

Answer 5

i dont understand this step:
16x(4x+7) + 6y(4x+7)

Answer 6

64x^2 + 112x + 24xy + 42y

8x( `8x+14`) + 6y(4x + 7)

16x(4x+7) + 6y(4x+7)

Answer 7

factor "2" from that

Answer 8

you mean
8x(4x + 7)?
or
4x(4x + 7)?

Answer 9

i think i understand it now.
i used 8x to factor but that was too little. i noticed from (8x + 14) i could factor out a 2 which means that i would have to multiply the 8x that i used by 2. so instead the correct factors are (16x + 6y) (4x + 7) yes?

Answer 10

and then
(16x + 6y) can be factored with 2
so
2(8x +3y) (4x+7) is the answer.
i think.

Answer 11

Perfect !!!