if n!/(n-1)!=5 ,, then (n-2)! =? plz do help me ... ... i dont know how to do this question ...
what is n! defined as? what is (n-1)! defined as?
'expand' the factorials and youll be able to solve for n
if n=5 then, 5!/(5-1)!=5 therefore (5-2)!=3! i.e 3x2x1=6
@cj49 from where 3(2)(1) came ?
the factorial of a non-negative integer n, denoted by n!, is the product of all positive integers less than or equal to n.
for eg 5!=5x4x3x2x1=120
ahh :O
can u tell me what is this ! ??
!=factorial
\(\Large n! = n\times (n-1)\times (n-2)\times ... \times 3\times 2\times 1\) example \(\Large 7! = 7\times6\times5\times4\times3\times2\times1\)
\(\Large n! = n\times [(n-1)\times (n-2)\times ... \times 3\times 2\times 1] \\ \Large = n \times (n-1)!\)
thank u so much @cj49 & @hartnn thsnkx alot for helping me :D
np c:
:) `
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