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What is an equation of the tangent line at x = 5, assuming that y(5) = 4 and y'(5) = 2?
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We have all the information we need to fill in the blanks. No real math is needed. Recall the equation of a tangent line is a line and therefore can be written as y-y1=m(x-x1) Where m is the slope at x=x1 and (x1,y1) is a point on the curve
So it would be the points (5,4) (5,2)?
I only see on point on y that is (5,4)
The other equation you wrote is giving you the slope at x=5
That little ' denotes derivative (slope)
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Oh! so the slope is 2? so it would be y-4=(2(x-5)
looks good
wow thank you so much for your help!!
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