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integral(sin^5(x)/(1+cos^2(x))dx super confused :(
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I don't even know how to begin starting this... \[\int\limits(\sin^5(x)/(1+\cos^2(x))dx\]
im sorry, this ones' a little too difficult for me. sorry.
I'm in Calculus II DX
\[\int\limits(\frac{ (1-\cos^2(x))(1-\cos^2(x))(1-\cos^2(x) )}{ 1+\cos^2(x) }dx\] Am i doing this right....
im sorry, im not sure, im taking calculus next semester. :(
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it needs to be done by substitution method...
separate sin^5x into sin^4x * sinx and then suppose u=cosx do derivative then you get du=sinx dx after that it might be easy....all the trig function will go away...
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