Mathematics
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OpenStudy (anonymous):
Let f(x) = 12 over the quantity of 4 x + 2. Find f(-1).
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OpenStudy (anonymous):
-6
-2
2
6
OpenStudy (anonymous):
@kirbykirby @wyattp17 @Jacob_Junior
OpenStudy (anonymous):
@PaulaLovesSchool13
OpenStudy (anonymous):
.....
OpenStudy (anonymous):
Reminder: I am not the best in math XD
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hartnn (hartnn):
to get f(-1), just plug in x=-1 in f(x)!
OpenStudy (anonymous):
is it -6
OpenStudy (anonymous):
or 6
hartnn (hartnn):
\(\large f(x) = \dfrac{12}{4x+2} \\ \Large f(-1) = \dfrac{12}{4(-1)+2} = ... ?\)
hartnn (hartnn):
yes!
-6 is correct :)
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OpenStudy (anonymous):
Let f(x) = 2x - 6. Solve f-1(x) when x = 2.
-5
4
-2
7
OpenStudy (anonymous):
is it b
hartnn (hartnn):
2x-6 = 2
YES! answer is 4, good! :)
OpenStudy (anonymous):
Let f(x) = x + 8 and g(x) = x2 - 6x - 7. Find f(g(2)).
-7
-3
10
33
OpenStudy (anonymous):
here i dont know what to do
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hartnn (hartnn):
find g(2) first, as usual
hartnn (hartnn):
plug in x=2 in g(x) to get g(2)
OpenStudy (anonymous):
-15 + 8
hartnn (hartnn):
excellent work!
hartnn (hartnn):
-7 is correct :)
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OpenStudy (anonymous):
can u help me with two more
OpenStudy (anonymous):
Let f(x) = x - 2 and g(x) = x2 - 7x - 9. Find f(g(-1)).
-21
-3
3
21
hartnn (hartnn):
sure :)
hartnn (hartnn):
whats g(-1) ?
plug in x=-1 in g(x)
OpenStudy (anonymous):
Let f(x) = x2 - 81. Find f-1(x).
±square root of the quantity x plus 81
9square root of x
1 over quantity x squared minus 81
x squared over 81
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OpenStudy (anonymous):
the llast oone i think its c
OpenStudy (anonymous):
and the 1 -21
OpenStudy (anonymous):
am i right
OpenStudy (anonymous):
good explaining Taylor! Wear this medal :)
OpenStudy (anonymous):
@hartnn
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hartnn (hartnn):
f(g(-1)) is actually -3.
how u got -21 ?
OpenStudy (anonymous):
i just did 7times 3
hartnn (hartnn):
g(-1) = 1 - 7(-1) - 9 = 1+7-9 = -1
f(x) = x - 2 , f(-1) = -1-2 =-3
hartnn (hartnn):
y = x^2 - 81
try to isolate x from here, that will be your inverse function
OpenStudy (anonymous):
- 81 times 2
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hartnn (hartnn):
no...like this :
\(y = x^2 -81 \\ y+81 =x^2 \\x = \pm \sqrt {y+81} \)
hartnn (hartnn):
so your inverse function will be
square root of (x+81)
hartnn (hartnn):
"±square root of the quantity x plus 81"