Need help with Polynomial division and Rewriting expressions!!
If x=4y+1 and z=3x-5 find an expression for z in terms of y
If (2x^2+kx+3)/(x-3)=2x-1 find the value of k
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OpenStudy (anonymous):
You mean substitute it in?
OpenStudy (anonymous):
@mathstudent55
OpenStudy (cwrw238):
substitute x = 4y + 1 in z = 3x - 5
that is
replace x in the formula for z by 4y + 1
OpenStudy (cwrw238):
then simplify
OpenStudy (anonymous):
How does it simplify to 12y-2 though?
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OpenStudy (cwrw238):
z = 3(4y + 1) - 5
= 12y + 3 - 5
= 12y - 2
OpenStudy (anonymous):
and you did 3*1 which is why it remained "+3" correct?
OpenStudy (cwrw238):
for the second question
expand (x - 3)(2x - 1)
then compare term by term with 2x^2 + kx + 3
OpenStudy (cwrw238):
yes
OpenStudy (anonymous):
by expand you just mean multiply right?
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OpenStudy (cwrw238):
distribute 3 over the 4y and the 1 in the parentheses
OpenStudy (cwrw238):
yes
OpenStudy (anonymous):
compare term by term?
OpenStudy (anonymous):
Also thank you for the help
OpenStudy (cwrw238):
first multiply second parentheses by x then by -3 then simplify
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OpenStudy (cwrw238):
well you'll obtain an expression with 3 terms
one in x^2 , one in x and one a number
line this up with 2x^2 + kx + 3
and you'll see what k is
OpenStudy (anonymous):
Oh I simplify the number I get from (x - 3)(2x - 1)? than compare it