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Simplify (8 + 7i) + (2 − i). 10 + 6i 16 4 10 + 8i
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Simplify \[(8 +7i) + (2 - 1)\]
\((a+bi)+(c+di)=(a+c)+i(b+d)\)
wait is that -1 or -i ?
oops, it - i
wrote it wrong sorry
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\[(8 + 7i) + (2 - i) \]
you can just think of this as like algebra, treating \(i\) as a variable like \(x\), just add like-terms :)
(8 + 7i) + (2 - i) +i +i (8 + 8i) + 2
then -2?
o_o I'm not sure what you did there. It is much simpler than what you may think. Imagine the problem is written as \((8+7x)+(2-x)\) and imagine \(x=i\)
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so it's 10 + 6i
\(\checkmark\_\checkmark\)
i suck at math, that's what i did :D
ya 10+6i is perfect ;) hehe.
thanks!
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np!
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